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NEET · Biology · STD 12 - 6. evolution
In HardyWeinberg equation, the frequency of heterozygous individual is represented by
- A \(p^2\)
- B \(2pq\)
- C \(pq\)
- D \(q^2\)
Answer & Solution
Correct Answer
(B) \(2pq\)
Step-by-step Solution
Detailed explanation
(b) : In a stable population, for a gene with two alleles, ‘\(A\)’ (dominant) and ‘\(a\)’ (recessive), if the frequency of ‘\(A\)’ is \(p\) and the frequency of ‘\(a\)’ is \(q\), then the frequencies of the three possible genotypes (\(AA, Aa\) and \(aa\)) can be expressed by the Hardy Weinberg equation : \(p^2 + 2pq + q^2 = 1\)
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