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NEET · Biology · STD 11 - 10. Cell cycle and cell division

During which phase(s) of cell cycle, amount of \(DNA\) in a cell remains at \(4C\) level if the initial amount is denoted as \(2C\) ?

  1. A \(G_0\) and \(G_1\)
  2. B \(G_1\) and \(S\)
  3. C Only \(G_2\)
  4. D \(G_2\) and \(M\)
Verified Solution

Answer & Solution

Correct Answer

(C) Only \(G_2\)

Step-by-step Solution

Detailed explanation

(c) : A cell cycle is divided into \(S, G\) and \(M\ (CM)\) which lies between \(G_2\) and M phase).\(G_1\) or first growth phase is followed by \(S\) phase or synthesis phase. \(DNA\) replication occurs in \(S\) phase and \(DNA\) amount doubles up \(i.e.\), a cell with \(2C\ DNA \) in \(G_1\) phase will now have \(4C\ DNA\). \(G_2\) phase is second growth phase where \(DNA\) content remains \(4C\). \(M\) phase is the phase of division where \(DNA\) content either regains \(2C\) level (mitosis) or becomes halved.
\(i.e.\) \(1C\) (in meiosis). \(G_0\) phase is the phase of differentiation where cell contains \(DNA\) as in the same amount as its parent cell and does not divide further.