MHT CET · Physics · Mechanical Properties of Fluids
Work done in increasing the size of a soap bubble from radius of \(3 \mathrm{~cm}\) to \(5 \mathrm{~cm}\) in millijoule is nearly (surface tension of soap solution \(=0.03 \mathrm{Nm}^{-1}\) )
- A \(0.4 \pi\)
- B \(0.2 \pi\)
- C \(4 \pi\)
- D \(2 \pi\)
Answer & Solution
Correct Answer
(A) \(0.4 \pi\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{w}=8 \pi \mathrm{T}\left(\mathrm{r}_2^2-\mathrm{r}_1^2\right) \\ & =8 \pi \times 0.03(25-9) \times 10^{-4} \\ & =0.384 \pi \times 10^{-3} \mathrm{~J} \\ & =0.384 \pi \mathrm{mJ} \approx 0.4 \pi \mathrm{mJ}\end{aligned}\)
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