MHT CET · Physics · Electromagnetic Induction
When three inductors of same inductance 'L' are connected in series and 'I' is the current passing through the circuit. The energy stored in the circuit is
- A \(\frac{1}{2} \mathrm{~L} \mathrm{~I}^2\)
- B \(\frac{3}{2} \mathrm{~L} \mathrm{~I}^2\)
- C \(\frac{5}{2} \mathrm{~L} \mathrm{~I}^2\)
- D \(\frac{7}{2} \mathrm{~L} \mathrm{~I}^2\)
Answer & Solution
Correct Answer
(B) \(\frac{3}{2} \mathrm{~L} \mathrm{~I}^2\)
Step-by-step Solution
Detailed explanation
\(L_{eq} = L + L + L = 3L\) \(U = \frac{1}{2} L_{eq} I^2\)
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