MHT CET · Physics · Waves and Sound
When the observer moves towards a stationary source with velocity \(V_1\), the apparent frequency of emitted note is \(F_1\). When observer moves away from the source with velocity \(V_1\), the apparent frequency is \(F_2\). If \(V\) is the velocity of sound in air and \(F_1 / F_2=2\) then \(V / V_1\) is equal to
- A 3
- B 2
- C 1
- D 4
Answer & Solution
Correct Answer
(A) 3
Step-by-step Solution
Detailed explanation
\(F_1 = F \frac{V + V_1}{V}\) \(F_2 = F \frac{V - V_1}{V}\)
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