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MHT CET · Physics · Waves and Sound

When the observer moves towards a stationary source with velocity \(V_1\), the apparent frequency of emitted note is \(F_1\). When observer moves away from the source with velocity \(V_1\), the apparent frequency is \(F_2\). If \(V\) is the velocity of sound in air and \(F_1 / F_2=2\) then \(V / V_1\) is equal to

  1. A 3
  2. B 2
  3. C 1
  4. D 4
Verified Solution

Answer & Solution

Correct Answer

(A) 3

Step-by-step Solution

Detailed explanation

\(F_1 = F \frac{V + V_1}{V}\) \(F_2 = F \frac{V - V_1}{V}\)
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