MHT CET · Physics · Dual Nature of Matter
When the electron orbiting in hydrogen atom in its ground state moves to the third excited state, the de-Broglie wavelength associated with it
- A becomes zero.
- B remains unchanged.
- C will decrease.
- D will increase.
Answer & Solution
Correct Answer
(D) will increase.
Step-by-step Solution
Detailed explanation
As \(\mathrm{v} \propto \frac{1}{\mathrm{n}}\), we can also write
\(\therefore \quad m v \propto \frac{1}{n} \quad \Rightarrow p \propto \frac{1}{n}\)
Also,
\(\lambda=\frac{\mathrm{h}}{\mathrm{p}} \quad \Rightarrow \lambda \propto \mathrm{n}\)
\(\therefore \quad\) Wavelength will increase.
\(\therefore \quad m v \propto \frac{1}{n} \quad \Rightarrow p \propto \frac{1}{n}\)
Also,
\(\lambda=\frac{\mathrm{h}}{\mathrm{p}} \quad \Rightarrow \lambda \propto \mathrm{n}\)
\(\therefore \quad\) Wavelength will increase.
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