MHT CET · Physics · Electromagnetic Induction
When magnetic flux changes from \(6.5 \times 10^{-2} \mathrm{~Wb}\) to \(11 \times 10^{-2} \mathrm{~Wb}\) and the change in current is 0.03 A , the coefficient of mutual inductance will be
- A 1.0 H
- B 1.2 H
- C 1.5 H
- D 1.8 H
Answer & Solution
Correct Answer
(C) 1.5 H
Step-by-step Solution
Detailed explanation
\(\Delta \Phi = \Phi_2 - \Phi_1 = 11 \times 10^{-2} \mathrm{~Wb} - 6.5 \times 10^{-2} \mathrm{~Wb} = 4.5 \times 10^{-2} \mathrm{~Wb}\) \(M = \frac{\Delta \Phi}{\Delta I} = \frac{4.5 \times 10^{-2} \mathrm{~Wb}}{0.03 \mathrm{~A}} = 1.5 \mathrm{~H}\)
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