MHT CET · Physics · Dual Nature of Matter
When light of wavelength ' \(\lambda\) ' is incident on a photosensitive surface, photons of power ' \(\mathrm{P}\) ' are emitted. The number of photon ' \(\mathrm{n}\) ' emitted in time ' \(\mathrm{t}\) ' is \(\mathrm{h}\) = Planck's constant, \(\mathrm{c}=\) velocity of light in vacuum]
- A \(\frac{\mathrm{hc}}{\mathrm{P} \lambda \mathrm{t}}\)
- B \(\frac{\mathrm{P} \lambda}{\mathrm{htc}}\)
- C \(\frac{\mathrm{P} \lambda \mathrm{t}}{\mathrm{hc}}\)
- D \(\frac{\mathrm{hP}}{\lambda \mathrm{tc}}\)
Answer & Solution
Correct Answer
(C) \(\frac{\mathrm{P} \lambda \mathrm{t}}{\mathrm{hc}}\)
Step-by-step Solution
Detailed explanation
Power, \(\mathrm{P}=\frac{\text { Energy }}{\mathrm{t}}=\frac{\mathrm{nhc}}{\lambda \mathrm{t}}\)
\(
\therefore \mathrm{n}=\frac{\mathrm{p} \lambda \mathrm{t}}{\mathrm{hc}}
\)
\(
\therefore \mathrm{n}=\frac{\mathrm{p} \lambda \mathrm{t}}{\mathrm{hc}}
\)
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