MHT CET · Physics · Current Electricity
When cell of e.m.f. ' \(E_1{ }^{\prime}\) is connected to potentiometer wire, the balancing length is ' \(\ell_1{ }^{\prime}\). Another cell of e.m.f. ' \(E_2{ }^{\prime}\left(E_1>E_2\right)\) is connected so that two cells oppose each other, the balancing length is ' \(\ell_2{ }^{\prime}\). The ratio \(\mathrm{E}_1: \mathrm{E}_2\) is
- A \(\frac{\ell_1}{\ell_1+\ell_2}\)
- B \(\frac{\ell_1}{\ell_1-\ell_2}\)
- C \(\frac{\ell_1-\ell_2}{\ell_1}\)
- D \(\frac{\ell_1+\ell_2}{\ell_1-\ell_2}\)
Answer & Solution
Correct Answer
(B) \(\frac{\ell_1}{\ell_1-\ell_2}\)
Step-by-step Solution
Detailed explanation
\(E_1 = k\ell_1\) \(E_1 - E_2 = k\ell_2\)
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