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MHT CET · Physics · Current Electricity

When cell of E.M.F. ' \(E_1\) ' is connected to potentiometer wire, the balancing length is \(l_1\). Another cell of E.M.F. ' \(E_2\) ' \(\left(E_1 \gt E_2\right)\) is connected so that two cells oppose each other, then the balancing length is \(l_2\). The ratio \(\mathrm{E}_1: \mathrm{E}_2\) is

  1. A \(\frac{l_1}{l_1+l_2}\)
  2. B \(\frac{l_1}{l_1-l_2}\)
  3. C \(\frac{l_1+l_2}{l_1}\)
  4. D \(\frac{l_1+l_2}{l_1-l_2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{l_1}{l_1-l_2}\)

Step-by-step Solution

Detailed explanation

Using sum and difference method,
\(\frac{\mathrm{E}_1}{\mathrm{E}_2}=\frac{l_1}{l_1-l_2}\)