MHT CET · Physics · Atomic Physics

When an electron in hydrogen atom jumps from the fourth Bohr orbit to second Bohr orbit we get the

A Second line of Paschen series
B First line of pfund series
C Second line of Balmer
D First line of Balmer series

Verified Solution

Answer & Solution

Correct Answer

(C) Second line of Balmer

Step-by-step Solution

Detailed explanation

The wavelength of line in case of Balmer series is given by
\(\frac{1}{\lambda}=\mathrm{R}\left(\frac{1}{2^2}-\frac{1}{\mathrm{n}^2}\right)\), where \(\mathrm{n}=3,4,5, \ldots\) and \(\mathrm{R}=\) Rydberg constant.
So, for Balmer series, the transition takes from third orbit to second first line spectrum, fourth orbit to second for second line spectrum and so on. Hence, given transition represents second line of Balmer series.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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