MHT CET · Physics · Current Electricity
When a resistance of \(200 \Omega\) is connected in series with a galvanometer of resistance ' \(G\) ', its range is ' V '. To triple its range, a resistance of \(2000 \Omega\) is connected in series. The value of ' \(G\) ' is
- A \(200 \Omega\)
- B \(400 \Omega\)
- C \(600 \Omega\)
- D \(700 \Omega\)
Answer & Solution
Correct Answer
(D) \(700 \Omega\)
Step-by-step Solution
Detailed explanation
Using, \(R_s=\frac{V}{I_g}-G\) we get, for \(1_1^{\text {st }}\) case, \(200=\frac{\mathrm{V}}{\mathrm{I}_{\mathrm{g}}}-\mathrm{R}\)
....(i) and for \(2^{\text {nd }}\) case, \(2000=\frac{3 \mathrm{~V}}{\mathrm{I}_{\mathrm{g}}}-\mathrm{R}\)...(ii)
By subtracting equation (i) from (ii) we get,
\(\begin{array}{ll}
& \frac{\mathrm{V}}{\mathrm{I}_{\mathrm{g}}}=900 \\
\therefore \quad & \mathrm{R}=700 \Omega
\end{array}\)
....(i) and for \(2^{\text {nd }}\) case, \(2000=\frac{3 \mathrm{~V}}{\mathrm{I}_{\mathrm{g}}}-\mathrm{R}\)...(ii)
By subtracting equation (i) from (ii) we get,
\(\begin{array}{ll}
& \frac{\mathrm{V}}{\mathrm{I}_{\mathrm{g}}}=900 \\
\therefore \quad & \mathrm{R}=700 \Omega
\end{array}\)
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