MHT CET · Physics · Dual Nature of Matter
When a photosensitive surface is irradiated by light of wavelength ' \(\lambda_1\) ' and ' \(\lambda_2\) ', maximum kinetic energies of emitted photoelectrons are ' \(E_1\) ' and ' \(E_2\) ' respectively. The work function of photosensitive surface is
- A \(\frac{\left(\lambda_1 E_1-\lambda_2 E_2\right)}{\left(\lambda_2-\lambda_1\right)}\)
- B \(\frac{\left(\lambda_1 E_1+\lambda_2 E_2\right)}{\left(\lambda_2-\lambda_1\right)}\)
- C \(\frac{\left(\lambda_1 E_2-\lambda_2 E_1\right)}{\left(\lambda_2-\lambda_1\right)}\)
- D \(\frac{\left(\lambda_1 E_2+\lambda_2 E_1\right)}{\left(\lambda_2-\lambda_1\right)}\)
Answer & Solution
Correct Answer
(A) \(\frac{\left(\lambda_1 E_1-\lambda_2 E_2\right)}{\left(\lambda_2-\lambda_1\right)}\)
Step-by-step Solution
Detailed explanation
\( \begin{aligned} & \mathrm{E}_1=\frac{\mathrm{hc}}{\lambda_1}-\mathrm{W} \\ & \mathrm{E}_2=\frac{\mathrm{hc}}{\lambda_2}-\mathrm{W} \\ & \mathrm{E}_1 \lambda_1+\mathrm{W} \lambda_1=\mathrm{E}_2 \lambda_2+\mathrm{W} \lambda_2 \\ & \mathrm{~W}=\frac{\mathrm{E}_1 \lambda_1-\mathrm{E}_2 \lambda_2}{\lambda_2-\lambda_1} \end{aligned} \)
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