MHT CET · Physics · Mechanical Properties of Fluids
When a liquid of density ' \(\rho\) ' flows through a tube of diameter ' \(d\) ' with critical velocity ' \(\mathrm{V}\) ' then the Reynolds number is
\(\text { ( } \eta=\text { coefficient of viscosity of liquid) }\)
- A \(\frac{\eta \rho}{V d}\)
- B \(\frac{\mathrm{Vd}}{\rho \eta}\)
- C \(\frac{\mathrm{Vpd}}{\eta}\)
- D \(\frac{V \eta d}{\eta}\)
Answer & Solution
Correct Answer
(C) \(\frac{\mathrm{Vpd}}{\eta}\)
Step-by-step Solution
Detailed explanation
Dimensionless number that helps to find the dominant force between inertial force and viscous force. It is defined as,
\(\text { Reynold's number }=\frac{\text { inertial force }}{\text { viscous force }}=\left(\frac{\rho \mathrm{Vd}}{\eta}\right)\)
\(\text { Reynold's number }=\frac{\text { inertial force }}{\text { viscous force }}=\left(\frac{\rho \mathrm{Vd}}{\eta}\right)\)
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