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MHT CET · Physics · Laws of Motion

When a disc is rotating with angular velocity \(\omega\), a particle situated at a distance of \(4 \mathrm{~cm}\) just begins to slip. If the angular velocity is doubled, at what distance will the particle start to slip?

  1. A \(1 \mathrm{~cm}\)
  2. B \(2 \mathrm{~cm}\)
  3. C \(3 \mathrm{~cm}\)
  4. D \(4 \mathrm{~cm}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1 \mathrm{~cm}\)

Step-by-step Solution

Detailed explanation

Angular velocity \(=\omega\) Centripetal force \(F=m r \omega^{2}\)
or \(\quad r \propto \frac{1}{\omega^{2}}\)
\(\therefore\) \(\frac{r_{1}}{r_{2}}=\frac{\omega_{2}^{2}}{\omega_{1}^{2}}\)
or
\(\frac{4}{r_{2}}=\frac{4 \omega^{2}}{\omega^{2}}\)
or \(r_{2}=1 \mathrm{~cm}\)