MHT CET · Physics · Electromagnetic Induction
When a current of \(1 \mathrm{~A}\) is passed through a coil of 100 turns, the flux associated with it is \(2.5 \times 10^{-5} \mathrm{~Wb} /\) turn. The self inductance of the coil in millihenry is
- A \(40\)
- B \(25\)
- C \(4\)
- D \(2.5\)
Answer & Solution
Correct Answer
(D) \(2.5\)
Step-by-step Solution
Detailed explanation
Given: \(N=100, I=1 \mathrm{~A}\), \(\phi=2.5 \times 10^{-5} \mathrm{~Wb} /\) turn
Self-inductance of coil,
\(\mathrm{L} =\frac{\mathrm{N} \phi}{\mathrm{I}}\)
\(\therefore \mathrm{L} =\frac{100 \times 2.5 \times 10^{-5}}{1}=2.5 \times 10^{-3} \mathrm{H}\) \(=2.5 \mathrm{mH}\)
Self-inductance of coil,
\(\mathrm{L} =\frac{\mathrm{N} \phi}{\mathrm{I}}\)
\(\therefore \mathrm{L} =\frac{100 \times 2.5 \times 10^{-5}}{1}=2.5 \times 10^{-3} \mathrm{H}\) \(=2.5 \mathrm{mH}\)
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