MHT CET · Physics · Alternating Current
When a capacitor is connected in series LR circuit, the alternating current flowing in the circuit
- A is zero.
- B increases.
- C decreases.
- D remain constant.
Answer & Solution
Correct Answer
(B) increases.
Step-by-step Solution
Detailed explanation
Impedance for L-R circuit,
\(\mathrm{Z}_1=\sqrt{\mathrm{R}^2+\mathrm{X}_{\mathrm{L}}^2}\)
Impedance for L-C-R circuit,
\(\begin{array}{ll}
\therefore \quad \mathrm{Z}_2 & =\sqrt{\mathrm{R}^2+\left(\mathrm{X}_{\mathrm{L}}-\mathrm{X}_{\mathrm{C}}\right)^2} \\
\therefore \quad \mathrm{Z}_2 & \lt \mathrm{Z}_{\mathrm{i}}
\end{array}\)
As impedance decreases, the current increases.
\(\mathrm{Z}_1=\sqrt{\mathrm{R}^2+\mathrm{X}_{\mathrm{L}}^2}\)
Impedance for L-C-R circuit,
\(\begin{array}{ll}
\therefore \quad \mathrm{Z}_2 & =\sqrt{\mathrm{R}^2+\left(\mathrm{X}_{\mathrm{L}}-\mathrm{X}_{\mathrm{C}}\right)^2} \\
\therefore \quad \mathrm{Z}_2 & \lt \mathrm{Z}_{\mathrm{i}}
\end{array}\)
As impedance decreases, the current increases.
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