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MHT CET · Physics · Mechanical Properties of Fluids

What should be the diameter of a soap bubble, in order that the excess pressure inside it is \(25.6 \mathrm{Nm}^{-2}\) ? [surface tension of soap solution \(\left.=3.2 \times 10^{-2} \mathrm{Nm}^{-2}\right]\)

  1. A \(2 \mathrm{~cm}\)
  2. B \(1.5 \mathrm{~cm}\)
  3. C \(1 \mathrm{~cm}\)
  4. D \(0.5 \mathrm{~cm}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(1 \mathrm{~cm}\)

Step-by-step Solution

Detailed explanation

The formula for excess pressure inside the bubble is given as \(P_0=\frac{4 T}{R}\)
Where, \(\mathrm{T}\) is surface tension and \(\mathrm{R}\) is the radius of the sphere
Rearranging the formula for \(\mathrm{R}\) and substituting the values,
\(\begin{aligned}
& R=\frac{4 T}{P_0} \\
& R=\frac{4 \times 3.2 \times 10^{-2}}{25.6} \\
& R=0.5 \times 10^{-2} \mathrm{~m}=0.5 \mathrm{~cm}
\end{aligned}\)
The diameter then becomes, \(2 \mathrm{R}=1 \mathrm{~cm}\)
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