What is the angle between resultant of \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}\) and \(\overrightarrow{\mathrm{A}} \times \overrightarrow{\mathrm{B}}\) ?

Given,
Two vectors A and B.
A and B are two vectors. So, their sum A + B lies in the same plane where A and B lie (Since they are non -parallel so they define a plane and the cross product between them is not zero.)
\(\mathrm{A} \times \mathrm{B}=|\mathrm{A}||\mathrm{B}| \sin \alpha \mathrm{n}\), where \(\alpha\) is the angle between \(\mathrm{A} \& \mathrm{~B}\) and \(\mathrm{n}\) is the unit vector perpendicular to the plane containing A \& B. So, the angle between \((\mathrm{A}+\mathrm{B})\) and \((\mathrm{A} \times \mathrm{B})\) is \(90^{\circ}\).
Mathematically,
\(|\mathrm{A}+\mathrm{B} \| \mathrm{A} \times \mathrm{B}| \cos \alpha=(\mathrm{A}+\mathrm{B}) \cdot(\mathrm{A} \times \mathrm{B})\)
\(=A \cdot(A \times B)+B \cdot(A \times B)\)
\(=B \cdot(A \times A)+A \cdot(B \times B)\)
\(=0+0\)