MHT CET · Physics · Mechanical Properties of Fluids
Water rises upto a height 'h' in a capillary tube on the surface of the earth. The value of ' \(\mathrm{h}\) ' will increase if the experimental setup is kept in \([\mathrm{g}=\) acceleration due
to gravity]
- A a lift going upward with a certain acceleration.
- B a lift going down with acceleration
- C accelerating train.
- D a satellite rotating close to earth.
Answer & Solution
Correct Answer
(B) a lift going down with acceleration
Step-by-step Solution
Detailed explanation
(D)
\(h=\frac{2 T \cos \theta}{r \rho g} \quad \therefore h \propto \frac{1}{g}\)
For a lift going down with acceleration \(a\), the effective value of \(g\) is \(g^{\prime}=g-a\) \(g^{\prime}=g-a\)
\(\mathrm{g}^{\prime} < \mathrm{g} \quad \therefore \mathrm{h}\) will increase.
\(h=\frac{2 T \cos \theta}{r \rho g} \quad \therefore h \propto \frac{1}{g}\)
For a lift going down with acceleration \(a\), the effective value of \(g\) is \(g^{\prime}=g-a\) \(g^{\prime}=g-a\)
\(\mathrm{g}^{\prime} < \mathrm{g} \quad \therefore \mathrm{h}\) will increase.
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