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MHT CET · Physics · Mechanical Properties of Fluids

Water rises in a capillary tube of radius \(\mathrm{r}\) upto a height 'h'. The mass of water in a capillary is 'm'. The mass of water that will rise in a capillary of radius \(\frac{\mathrm{r}}{4}\) will be

  1. A \(\frac{m}{4}\)
  2. B \(\frac{4}{\mathrm{~m}}\)
  3. C 4m
  4. D m
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{m}{4}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{hr}=\) constant
\(\therefore\) rise of water in capillary of radius \(\frac{\mathrm{r}}{4}\) is \(4 \mathrm{~h}\)
Now, \(\pi \mathrm{r}^{2} \mathrm{~h} \rho=\mathrm{m}\)
\(\therefore \quad \pi\left(\frac{\mathrm{r}}{4}\right)^{2} \times 4 \mathrm{~h} \rho=\frac{\mathrm{m}}{4}\)
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