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MHT CET · Physics · Mechanical Properties of Fluids

Water rises in a capillary tube of radius ' \(r\) ' up to height ' \(h\) '. The mass of water in capillary is ' \(m\) '. The mass of water that will rise in capillary of radius \(\mathrm{r} / 3\) will be

  1. A m
  2. B \(\frac{\mathrm{m}}{3}\)
  3. C \(\frac{m}{6}\)
  4. D \(\frac{\mathrm{m}}{9}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{\mathrm{m}}{3}\)

Step-by-step Solution

Detailed explanation

Rise of water in capillary tube is given by
\(\mathrm{h}=\frac{2 \mathrm{~T} \cos \theta}{\mathrm{rgg}}\)
For water, \(\cos \theta=1\)
Also, the radius of capillary tube becomes (r/3).\(
\therefore \quad \mathrm{h}^{\prime}=\frac{3 \cdot 2 \mathrm{~T}}{\mathrm{r} \rho \mathrm{~g}} \Rightarrow \mathrm{~h}^{\prime}=3 \mathrm{~h}\)
Now, \(m=\pi r^2 \mathrm{~h} \times \rho\)
\(\therefore \quad \mathrm{m}^{\prime}=\pi(\mathrm{r} / 3)^2(3 \mathrm{~h}) \times \rho=\frac{\pi \mathrm{r}^2 \mathrm{~h} \rho}{3}=\frac{\mathrm{m}}{3}\)
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