MHT CET · Physics · Mechanical Properties of Fluids
Water is flowing through a horizontal pipe of non-uniform cross-section. In the region of narrowest part inside the pipe, the water will have
- A maximum velocity and minimum pressure.
- B both the pressure and velocity maximum.
- C both the pressure and velocity minimum.
- D maximum pressure and minimum velocity.
Answer & Solution
Correct Answer
(A) maximum velocity and minimum pressure.
Step-by-step Solution
Detailed explanation
By equation of continuity
\(\mathrm{A}_{1} \mathrm{~V}_{1}=\mathrm{A}_{2} \mathrm{~V}_{2}\)
Hence if area of cross-section decreases, the velocity increases.
By Bernoulli's equation
\(p+\frac{1}{2} \rho V^{2}=\text { constant }\)
\(\therefore\) if \(V\) increase pressure decreases.
Hence in the narrowest part, velocity is maximum and pressure is minimum.
\(\mathrm{A}_{1} \mathrm{~V}_{1}=\mathrm{A}_{2} \mathrm{~V}_{2}\)
Hence if area of cross-section decreases, the velocity increases.
By Bernoulli's equation
\(p+\frac{1}{2} \rho V^{2}=\text { constant }\)
\(\therefore\) if \(V\) increase pressure decreases.
Hence in the narrowest part, velocity is maximum and pressure is minimum.
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