MHT CET · Physics · Mechanical Properties of Fluids
Water is flowing through a horizontal pipe in stream line flow. At the narrowest part of the pipe
- A velocity is maximum and pressure is minimum
- B pressure is maximum and velocity is minimum
- C both pressure and velocity are minimum
- D both pressure and velocity are maximum
Answer & Solution
Correct Answer
(A) velocity is maximum and pressure is minimum
Step-by-step Solution
Detailed explanation
Using equation of continuity,
\(\mathrm{A}_1 \mathrm{~V}_1=\mathrm{A}_2 \mathrm{~V}_2\)
In streamlined flow, as the product of \(\mathrm{Av}\) is a constant, the velocity at the narrowest part will be maximum.
By using Bernoulli's principle,
\(\mathrm{P}+\frac{1}{2} \rho v^2+\rho g h=\text { Constant }\)
We see that \(\rho g h\) is constant because the pipe is horizontal.
As velocity increases, for the equation to remain constant, \(\mathrm{P}\) has to decrease.
\(\therefore \quad\) Velocity will be maximum and pressure is minimum
\(\mathrm{A}_1 \mathrm{~V}_1=\mathrm{A}_2 \mathrm{~V}_2\)
In streamlined flow, as the product of \(\mathrm{Av}\) is a constant, the velocity at the narrowest part will be maximum.
By using Bernoulli's principle,
\(\mathrm{P}+\frac{1}{2} \rho v^2+\rho g h=\text { Constant }\)
We see that \(\rho g h\) is constant because the pipe is horizontal.
As velocity increases, for the equation to remain constant, \(\mathrm{P}\) has to decrease.
\(\therefore \quad\) Velocity will be maximum and pressure is minimum
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