MHT CET · Physics · Mathematics in Physics
Vector \(\vec{A}\) of magnitude \(5 \sqrt{3}\) units, another vector \(\vec{B}\) of magnitude of 10 units are inclined to each other at an angle of \(30^{\circ}\). The magnitude of vector product of the two vectors is \(\left[\sin 30^{\circ}=\frac{1}{2}\right]\)
- A \(5 \sqrt{3}\) units
- B 10 units
- C \(25 \sqrt{3}\) units
- D 75 units
Answer & Solution
Correct Answer
(C) \(25 \sqrt{3}\) units
Step-by-step Solution
Detailed explanation
\(|\vec{A} \times \vec{B}| = AB \sin \theta \) \(|\vec{A} \times \vec{B}| = (5 \sqrt{3})(10) \sin 30^{\circ} = (5 \sqrt{3})(10) \left(\frac{1}{2}\right) = 25 \sqrt{3} \) units
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