MHT CET · Physics · Atomic Physics
Using Bohr's quantization condition, the rotational kinetic energy in the third orbit for a diatomic molecule is ( \(h=\) Planck's constant, \(I=\) moment of inertia of diatomic molecule)
- A \(\frac{9 h^2}{8 \pi^2 I}\)
- B \(\frac{3 \mathrm{~h}^2}{8 \pi^2 \mathrm{I}}\)
- C \(\frac{6 \mathrm{~h}^2}{8 \pi \mathrm{I}}\)
- D \(\frac{12 h^2}{7 \pi^2 I}\)
Answer & Solution
Correct Answer
(A) \(\frac{9 h^2}{8 \pi^2 I}\)
Step-by-step Solution
Detailed explanation
L = \(n\frac{h}{2\pi}\) L = \(3\frac{h}{2\pi}\)
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