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MHT CET · Physics · Oscillations

\(U\) is the PE of an oscillating particle and \(F\) is the force acting on it at a given instant. Which of the following is true ?

  1. A \(\frac{U}{F}+x=0\)
  2. B \(\frac{2 U}{F}+x=0\)
  3. C \(\frac{F}{U}+x=0\)
  4. D \(\frac{F}{2 U}+x=0\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{2 U}{F}+x=0\)

Step-by-step Solution

Detailed explanation

The potential energy, \(U=\frac{1}{2} k x^{2}\)
\(
2 U=k x^{2}
\)
or
\(
\begin{array}{l}
2 U=-F x \quad[\because F=-k x] \\
\frac{2 U}{F}=-x
\end{array}
\)
or
\(
\frac{2 U}{F}+x=0
\)
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