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MHT CET · Physics · Magnetic Effects of Current

Two wires of same length are made to from a circle and a square. They carry same current. The ratio of the magnetic moment of circle to that of square is

  1. A \(4: \pi\)
  2. B \(2: \pi\)
  3. C \(\pi: 4\)
  4. D \(\pi: 2\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(4: \pi\)

Step-by-step Solution

Detailed explanation

Let length of wire be \(l\). For a square loop, side of square \(\frac{l}{4}\).
Hence its magnetic moment
\(M_{\mathrm{sq}}=i A=i\left[\frac{l}{4}\right]^2=\frac{i l^2}{16}\)
Radius of a circular loop \(r=\frac{l}{2 \pi}\)
Hence, its magnetic moment
\(\begin{aligned} & M_{\mathrm{cir}}=i A=i \pi r^2 \\ & M_{\text {cir }}=i \pi\left[\frac{l^2}{4 \pi r^2}\right]=\frac{i l^2}{4 \pi} \\ & \Rightarrow \frac{M_{\text {cir }}}{M_{\mathrm{sq}}}=\frac{4}{\pi}\end{aligned}\)