MHT CET · Physics · Waves and Sound
Two waves \(y_1=0.35 \sin (316 t)\) and \(y_2=0.35 \sin (310 t)\) are propagating along the same direction. The number of beats produced per second are
- A \(\frac{3}{\pi}\)
- B \(\frac{2}{\pi}\)
- C \(\frac{\pi}{2}\)
- D \(\frac{\pi}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{3}{\pi}\)
Step-by-step Solution
Detailed explanation
According to question:
\(f_1=\frac{316}{2 \pi}\)
and,
\(f_2=\frac{310}{2 \pi}\)
Now,
The number of beats heard per second \(=f_1-f_2=\frac{316}{2 \pi}-\frac{310}{2 \pi}=\frac{3}{\pi}\)
\(f_1=\frac{316}{2 \pi}\)
and,
\(f_2=\frac{310}{2 \pi}\)
Now,
The number of beats heard per second \(=f_1-f_2=\frac{316}{2 \pi}-\frac{310}{2 \pi}=\frac{3}{\pi}\)
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