MHT CET · Physics · Waves and Sound
Two waves are represented by the equation, \(\mathrm{y}_1=\mathrm{A} \sin (\omega \mathrm{t}+\mathrm{kx}+0.57) \mathrm{m}\) and \(\mathrm{y}_2=\mathrm{A} \cos (\omega \mathrm{t}+\mathrm{kx}) \mathrm{m}\), where \(\mathrm{x}\) is in metre and \(\mathrm{t}\) is in second. What is the phase difference between them?
- A 0.57 radian
- B 1.0 radian
- C 1.57 radian
- D 1.25 radian
Answer & Solution
Correct Answer
(B) 1.0 radian
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{y}_1=\mathrm{A} \sin (\omega \mathrm{t}+\mathrm{kx}+0.57) \\ & \mathrm{y}_2=\mathrm{A} \cos (\omega \mathrm{t}+\mathrm{kx})=\mathrm{A} \sin \left(\omega \mathrm{t}+\mathrm{kx}+\frac{\pi}{2}\right) \\ & \therefore \text { Phase difference }=\frac{\pi}{2}-0.57 \\ & =\frac{3.14}{2}-0.57 \\ & =1.57-0.57=1.0 \mathrm{rad}\end{aligned}\)
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