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MHT CET · Physics · Wave Optics

Two wavelengths of sodium light \(590 \mathrm{~nm}\) and \(596 \mathrm{~nm}\) are used one after another to study diffraction due to single slit of aperture \(2 \times 10^{-6} \mathrm{~m}\). The distance between the slit and the screen is \(1.5 \mathrm{~m}\). The separation between the positions of first maximum of the diffraction pattern obtained in the two cases is

  1. A \(5.5mm\)
  2. B \(5.75mm\)
  3. C \(6.25mm\)
  4. D \(6.75mm\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(6.75mm\)

Step-by-step Solution

Detailed explanation

First maximum in single slit diffraction pattern is obtained at, \(x=\frac{3 \lambda D}{2 d}\)
\(\begin{array}{ll}
\therefore & \Delta \mathrm{x}=\frac{3 \mathrm{D} \times \Delta \lambda}{2 \mathrm{~d}}=\frac{3 \times 1.5}{2 \times 2 \times 10^{-6}}(596-590) \\
\therefore & \Delta \mathrm{x}=6.75 \mathrm{~mm}
\end{array}\)
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