MHT CET · Physics · Waves and Sound
Two uniform wires of same material are vibrating under the same tension. If the \(1^{\text {st }}\) overtone of \(1^{\text {st }}\) wire is equal to the \(2^{\text {nd }}\) overtone of \(2^{\text {nd }}\) wire and radius of \(1^{\text {st }}\) wire is twice the radius of \(2^{\text {nd }}\) wire, the ratio of length of \(1^{\text {st }}\) wire to that \(2^{\text {nd }}\) wire is
- A \(1: 3\)
- B \(3: 1\)
- C \(2: 3\)
- D \(3: 5\)
Answer & Solution
Correct Answer
(A) \(1: 3\)
Step-by-step Solution
Detailed explanation
\( f = \frac{n}{2L} \sqrt{\frac{T}{\rho \pi r^2}} \) \( f_{1,1st\_overtone} = f_{2,2nd\_overtone} \)
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