MHT CET · Physics · Motion In One Dimension
Two trains, each \(30 \mathrm{~m}\) long are travelling in opposite directions with velocities \(5 \mathrm{~m} / \mathrm{s}\) and \(10 \mathrm{~m} / \mathrm{s}\). They will cross after
- A \(4 \mathrm{~s}\)
- B \(3 \mathrm{~s}\)
- C \(2 \mathrm{~s}\)
- D \(1 \mathrm{~s}\)
Answer & Solution
Correct Answer
(A) \(4 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
Relative velocity of one train w. r. t other \(=5+0\)
\(=15 \mathrm{~m} / \mathrm{s}\)
Total length to cross \((\mathrm{L})=30+30=60 \mathrm{~m}\)
\(\therefore \quad t=\frac{L}{V}=\frac{60}{15}=4 s\)
\(=15 \mathrm{~m} / \mathrm{s}\)
Total length to cross \((\mathrm{L})=30+30=60 \mathrm{~m}\)
\(\therefore \quad t=\frac{L}{V}=\frac{60}{15}=4 s\)
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