MHT CET · Physics · Electrostatics
Two surfaces \(A\) and \(B\) are enclosing the charges as shown below. The total normal electric induction (T.N.E.I) through the surfaces A and B are respectively.
- A \(+2 q\) and \(+2 q\)
- B \(+q\) and \(+3 q\)
- C \(+q\) and \(+2 q\)
- D \(+2 q\) and \(+3 q\)
Answer & Solution
Correct Answer
(C) \(+q\) and \(+2 q\)
Step-by-step Solution
Detailed explanation
Total normal electric induction is given by,
\(\text {T.N.E.I. }=\sum q_{\text {enclosed }}\)
\(\therefore \text {T.N.E.I. for } A=(+2 q-q)=+q\)
\(\text { T.N.E.I. for } B=(+3 q-q)=+2 q\)
\(\text {T.N.E.I. }=\sum q_{\text {enclosed }}\)
\(\therefore \text {T.N.E.I. for } A=(+2 q-q)=+q\)
\(\text { T.N.E.I. for } B=(+3 q-q)=+2 q\)
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