MHT CET · Physics · Motion In Two Dimensions
Two stones of masses \(\mathrm{m}\) and \(3 \mathrm{~m}\) are whirled in horizontal circles, the heavier one in radius \(\left(\frac{\mathrm{r}}{3}\right)\) and lighter one in radius ' \(\mathrm{r}^{\prime}\). The tangential speed of lighter stone is 'n' times that of the value of heavier stone, when they experience same centripetal force. The value of \(\mathrm{n}\) is
- A 2
- B 3
- C 1
- D 4
Answer & Solution
Correct Answer
(B) 3
Step-by-step Solution
Detailed explanation
Centripetal force \(=\frac{\mathrm{mV}_{1}^{2}}{\mathrm{r}}=\frac{3 \mathrm{mV}_{2}^{2}}{\left(\frac{\mathrm{r}}{3}\right)}\)
\(\begin{aligned} \frac{\mathrm{V}_{1}^{2}}{\mathrm{~V}_{2}^{2}} &=9 \\ \frac{\mathrm{V}_{1}^{2}}{\mathrm{~V}_{2}^{2}} &=3 \end{aligned}\)
\(\begin{aligned} \frac{\mathrm{V}_{1}^{2}}{\mathrm{~V}_{2}^{2}} &=9 \\ \frac{\mathrm{V}_{1}^{2}}{\mathrm{~V}_{2}^{2}} &=3 \end{aligned}\)
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