MHT CET · Physics · Work Power Energy
Two springs of spring constants ' \(\mathrm{K}^{\prime}\) and ' \(2 \mathrm{~K}^{\prime}\) are stretched by same force. If ' \(\mathrm{w}_{1}{ }^{\circ}\) and ' \(\mathrm{w}_{2}\) ' are the energies stored in them respectively then
- A \(\mathrm{w}_{1}=2 \mathrm{w}_{2}\)
- B \(\mathrm{w}_{1}=\frac{\mathrm{w}_{2}}{4}\)
- C \(\mathrm{w}_{2}=2 \mathrm{w}_{1}\)
- D \(\mathrm{w}_{1}=\mathrm{w}_{2}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{w}_{1}=2 \mathrm{w}_{2}\)
Step-by-step Solution
Detailed explanation
Energy stored in spring of
\(w_{1}=\frac{1}{2} k x^{2} \text { constant } k\)
Th spring of contant 2k
\(w_{2}=\frac{1}{2} (2k) x^{2} \text { constant } k\)
So, \(w_{2}=2w_{1}\)
\(w_{1}=\frac{1}{2} k x^{2} \text { constant } k\)
Th spring of contant 2k
\(w_{2}=\frac{1}{2} (2k) x^{2} \text { constant } k\)
So, \(w_{2}=2w_{1}\)
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