ExamBro
ExamBro
MHT CET · Physics · Thermal Properties of Matter

Two spherical black bodies of radius ' \(\mathrm{r}_{1}\) ' and ' \(\mathrm{r}_{2}\) ' with surface temperature ' \(\mathrm{T}_{1}\) ' and
\({ }^{\prime} \mathrm{T}_{2}\) ' respectively, radiate same power, then \(\mathrm{r}_{1}: \mathrm{r}_{2}\) is

  1. A \(\left(\frac{\mathrm{T}_{2}}{\mathrm{~T}_{1}}\right)^{2}\)
  2. B \(\left(\frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}\right)^{4}\)
  3. C \(\left(\frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}\right)^{2}\)
  4. D \(\left(\frac{\mathrm{T}_{2}}{\mathrm{~T}_{1}}\right)^{4}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\left(\frac{\mathrm{T}_{2}}{\mathrm{~T}_{1}}\right)^{2}\)

Step-by-step Solution

Detailed explanation

(A)
\(4 \pi r_{1}^{2} T_{1}^{4}=4 \pi r_{2}^{2} T_{2}^{4}\)
\(\frac{r_{1}^{2}}{r_{2}^{2}}=\frac{T_{2}^{4}}{T_{1}^{4}}\)
\(\frac{r_{1}}{r_{2}}=\frac{T_{2}^{2}}{T_{1}^{2}}\)
Same subject
Explore more questions on app