MHT CET · Physics · Gravitation
Two satellites \(A\) and \(B\) having ratio of masses \(3: 1\) are revolving in circular orbits of radii ' \(r\) ' and ' 4 r '. The ratio of total energy of satellites A to that of \(B\) is
- A \(1: 3\)
- B \(3: 1\)
- C \(3: 4\)
- D \(12: 1\)
Answer & Solution
Correct Answer
(D) \(12: 1\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \frac{E_A}{E_B} & =\frac{M_A}{M_B} \times \frac{r_B}{r_A} \quad \ldots\left(E \propto \frac{M}{r}\right) \\ & =\frac{3}{1} \times \frac{4 r}{r} \\ \frac{E_A}{E_B} & =\frac{12}{1}\end{aligned}\)
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