MHT CET · Physics · Nuclear Physics
Two radioactive materials ' \(M_1{ }^{\prime}\) and ' \(M_2{ }^{\prime}\) have decay constants ' \(9 \lambda\) ' and ' \(\lambda\) ' respectively. Initially they have the same number of nuclei. The ratio of the number of nuclei of \(M_1\) to that of \(M_2\) will be ' \(\left(\frac{1}{e}\right)^{\prime}\) after a time interval
- A \(\frac{9}{10 \lambda}\)
- B \(\frac{1}{10 \lambda}\)
- C \(\frac{1}{9 \lambda}\)
- D \(\frac{1}{8 \lambda}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{8 \lambda}\)
Step-by-step Solution
Detailed explanation
\( \frac{N_1(t)}{N_2(t)} = \frac{N_0 e^{-9\lambda t}}{N_0 e^{-\lambda t}} \) \( \frac{1}{e} = e^{-9\lambda t + \lambda t} \)
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