MHT CET · Physics · Waves and Sound
Two progressive waves are travelling towards each other with velocity \(50 \mathrm{~m} / \mathrm{s}\) and frequency \(200 \mathrm{~Hz}\). The distance between the two consecutive antinodes is
- A \(0.125 \mathrm{~m}\)
- B \(0.150 \mathrm{~m}\)
- C \(0.175 \mathrm{~m}\)
- D \(0.200 \mathrm{~m}\)
Answer & Solution
Correct Answer
(A) \(0.125 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Velocity of wave, \(v=f \lambda\)
\(\therefore \quad \lambda=\frac{\mathrm{v}}{\mathrm{f}}=\frac{50}{200}=0.25 \mathrm{~m}\)
\(\therefore \quad\) Dividing the wavelength for antinodes:
\(\begin{aligned}
\lambda & =\frac{0.25}{2} \\
& =0.125 \mathrm{~m}
\end{aligned}\)
\(\therefore \quad \lambda=\frac{\mathrm{v}}{\mathrm{f}}=\frac{50}{200}=0.25 \mathrm{~m}\)
\(\therefore \quad\) Dividing the wavelength for antinodes:
\(\begin{aligned}
\lambda & =\frac{0.25}{2} \\
& =0.125 \mathrm{~m}
\end{aligned}\)
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