MHT CET · Physics · Waves and Sound
Two progressive waves are travelling towards each other with velocity \(50 \mathrm{~m} / \mathrm{s}\) and frequency \(200 \mathrm{~Hz}\). The distance between two consecutive antinodes is
- A \(0 \cdot 031 \mathrm{~m}\)
- B \(0 \cdot 125 \mathrm{~m}\)
- C \(0 \cdot 250 \mathrm{~m}\)
- D \(0 \cdot 0625 \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(0 \cdot 125 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
AS,
\(\begin{aligned}
f &=\frac{v}{\lambda} \quad[v=50 \mathrm{~m} / \mathrm{s}] \\
\therefore \lambda &=\frac{50}{200}=1 / 4
\end{aligned}\)
Now, Distance blw two antinode \(=1 / 2\)
\(\begin{array}{r}=1 / 8=0.125 \mathrm{~m} \\ \text { < option-2 }\end{array}\)
\(\begin{aligned}
f &=\frac{v}{\lambda} \quad[v=50 \mathrm{~m} / \mathrm{s}] \\
\therefore \lambda &=\frac{50}{200}=1 / 4
\end{aligned}\)
Now, Distance blw two antinode \(=1 / 2\)
\(\begin{array}{r}=1 / 8=0.125 \mathrm{~m} \\ \text { < option-2 }\end{array}\)
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