MHT CET · Physics · Electrostatics
Two point charges +8 q and -2 q are located at \(\mathrm{X}=0\) (origin) and \(\mathrm{X}=\mathrm{L}\) respectively. The net electric field due to these two charges is zero at point P on X -axis. The location of point P from the origin is
- A \(\frac{\mathrm{L}}{4}\)
- B 2 L
- C 4 L
- D 8 L
Answer & Solution
Correct Answer
(B) 2 L
Step-by-step Solution
Detailed explanation
\(\begin{array}{ll}
& \frac{1}{4 \pi \varepsilon_0} \frac{8 q}{(L+d)^2}-\frac{1}{4 \pi \varepsilon_0} \frac{2 q}{d^2}=0 \\
& (L+d)^2=4 d^2 \\
\therefore \quad & L=d
\end{array}\)
Hence, the distance from the origin is 2 L .
& \frac{1}{4 \pi \varepsilon_0} \frac{8 q}{(L+d)^2}-\frac{1}{4 \pi \varepsilon_0} \frac{2 q}{d^2}=0 \\
& (L+d)^2=4 d^2 \\
\therefore \quad & L=d
\end{array}\)
Hence, the distance from the origin is 2 L .
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