MHT CET · Physics · Electromagnetic Induction
Two planar concentric rings of metal wire having radii \(r_1\) and \(r_2\) ( \(r_1>r_2\) ) are placed in air. The current I is flowing through the coil of larger radius. The mutual inductance between the coils is given by ( \(\mu_0=\) permeability of free space)
- A \(\frac{\mu_0 \pi r_1^2}{2 r_2}\)
- B \(\frac{\mu_0 \pi r_2^2}{2 r_1}\)
- C \(\frac{\mu_0 \pi\left(r_1+r_2\right)^2}{2 r_1}\)
- D \(\frac{\mu_0 \pi\left(r_1-r_2\right)^2}{2 r_2}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mu_0 \pi r_2^2}{2 r_1}\)
Step-by-step Solution
Detailed explanation
\(B_1 = \frac{\mu_0 I}{2 r_1}\) \(\Phi_2 = B_1 A_2 = \left(\frac{\mu_0 I}{2 r_1}\right) (\pi r_2^2)\)
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