MHT CET · Physics · Oscillations
Two particles 'A' and 'B' execute SHMs of periods 'T' and \('\left.\frac{3 T}{2}\right.'\). If they start from the mean position then the phase difference between them, when the particle 'A' completes two oscillations will be
- A \(\frac{\pi}{3}\)
- B \(\frac{\pi}{6}\)
- C \(\frac{4 \pi}{3}\)
- D \(\frac{\pi}{4}\)
Answer & Solution
Correct Answer
(C) \(\frac{4 \pi}{3}\)
Step-by-step Solution
Detailed explanation
\(t = 2 T_A = 2T\) \(\phi_A = \frac{2\pi}{T_A} t = \frac{2\pi}{T} (2T) = 4\pi\)
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