MHT CET · Physics · Magnetic Effects of Current
Two parallel wires separated by distance 'b' are carrying equal current 'I' in the same direction. The force per unit length of the wire is
- A \(\frac{\mu_0}{4 \pi}\left(\frac{\mathrm{I}}{\mathrm{b}^2}\right)\)
- B \(\frac{\mu_0}{4 \pi}\left(\frac{I^2}{b^2}\right)\).
- C \(\frac{\mu_0}{4 \pi}\left(\frac{I^2}{b}\right)\)
- D \(\frac{\mu_0}{4 \pi}\left(\frac{2 I^2}{b}\right)\)
Answer & Solution
Correct Answer
(D) \(\frac{\mu_0}{4 \pi}\left(\frac{2 I^2}{b}\right)\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \frac{\mathrm{F}}{l}=\frac{\mu_0}{4 \pi} \frac{2 \mathrm{I}_1 \mathrm{I}_2}{\mathrm{r}} \\ \therefore \quad & \frac{\mathrm{F}}{l}=\frac{\mu_0}{4 \pi} \frac{2 \mathrm{I}^2}{b} \\ \therefore \quad & \phi=60^{\circ}=\pi / 3\end{aligned}\)
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