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MHT CET · Physics · Thermodynamics

Two moles of an ideal monoatomic gas undergo a cyclic process as shown in figure. The temperatures in different states are given as \(6 \mathrm{~T}_1=3 \mathrm{~T}_2=2 \mathrm{~T}_4=\mathrm{T}_3=2400 \mathrm{~K}\). The work done by the gas during the complete cycle is ( \(R=\) Universal gas constant )
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  1. A \(-1600 \mathrm{R}\)
  2. B \(1600 R\)
  3. C \(-1200 \mathrm{R}\)
  4. D \(800 R\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(-1600 \mathrm{R}\)

Step-by-step Solution

Detailed explanation

\(P_1V_1 = nRT_1 = 2R(400 \mathrm{~K}) = 800R\) \(P_3V_1 = nRT_4 = 2R(1200 \mathrm{~K}) = 2400R\) (since \(P_3=P_4\) and \(V_1=V_4\))