MHT CET · Physics · Thermodynamics
Two moles of an ideal monoatomic gas undergo a cyclic process as shown in figure. The temperatures in different states are given as \(6 \mathrm{~T}_1=3 \mathrm{~T}_2=2 \mathrm{~T}_4=\mathrm{T}_3=2400 \mathrm{~K}\). The work done by the gas during the complete cycle is ( \(R=\) Universal gas constant )

- A \(-1600 \mathrm{R}\)
- B \(1600 R\)
- C \(-1200 \mathrm{R}\)
- D \(800 R\)
Answer & Solution
Correct Answer
(A) \(-1600 \mathrm{R}\)
Step-by-step Solution
Detailed explanation
\(P_1V_1 = nRT_1 = 2R(400 \mathrm{~K}) = 800R\) \(P_3V_1 = nRT_4 = 2R(1200 \mathrm{~K}) = 2400R\) (since \(P_3=P_4\) and \(V_1=V_4\))
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