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MHT CET · Physics · Center of Mass Momentum and Collision

Two masses ' \(\mathrm{m}_{\mathrm{a}}\) ' and ' \(\mathrm{m}_{\mathrm{b}}\) ' moving with velocities ' \(\mathrm{v}_{\mathrm{a}}\) ' and ' \(\mathrm{v}_{\mathrm{b}}\) ' opposite directions collide elastically. Alter the collision ' \(\mathrm{m}_{\mathrm{a}}\) ' and ' \(\mathrm{m}_{\mathrm{b}}\) ' move with velocities and ' \(\mathrm{v}_{\mathrm{b}}\) ' and ' \(\mathrm{v}_{\mathrm{a}}\) ' respectively, then the ratio \(\mathrm{m}_{\mathrm{a}}: \mathrm{m}_{\mathrm{b}}\) is

  1. A \(\frac{v_a+v_b}{v_a-v_b}\)
  2. B \(\frac{1}{2}\)
  3. C 1
  4. D \(\frac{v_a-v_b}{v_a+v_b}\)
Verified Solution

Answer & Solution

Correct Answer

(C) 1

Step-by-step Solution

Detailed explanation

When two bodies of equal masses collide elastically, they exchange their velocities. Since the two masses are exchanging their velocities, their masses must be equal.
Hence, \(\frac{\mathrm{m}_{\mathrm{a}}}{\mathrm{m}_{\mathrm{b}}}=1\)