MHT CET · Physics · Center of Mass Momentum and Collision
Two masses ' \(\mathrm{m}_{\mathrm{a}}\) ' and ' \(\mathrm{m}_{\mathrm{b}}\) ' moving with velocities ' \(\mathrm{v}_{\mathrm{a}}\) ' and ' \(\mathrm{v}_{\mathrm{b}}\) ' opposite directions collide elastically. Alter the collision ' \(\mathrm{m}_{\mathrm{a}}\) ' and ' \(\mathrm{m}_{\mathrm{b}}\) ' move with velocities and ' \(\mathrm{v}_{\mathrm{b}}\) ' and ' \(\mathrm{v}_{\mathrm{a}}\) ' respectively, then the ratio \(\mathrm{m}_{\mathrm{a}}: \mathrm{m}_{\mathrm{b}}\) is
- A \(\frac{v_a+v_b}{v_a-v_b}\)
- B \(\frac{1}{2}\)
- C 1
- D \(\frac{v_a-v_b}{v_a+v_b}\)
Answer & Solution
Correct Answer
(C) 1
Step-by-step Solution
Detailed explanation
When two bodies of equal masses collide elastically, they exchange their velocities. Since the two masses are exchanging their velocities, their masses must be equal.
Hence, \(\frac{\mathrm{m}_{\mathrm{a}}}{\mathrm{m}_{\mathrm{b}}}=1\)
Hence, \(\frac{\mathrm{m}_{\mathrm{a}}}{\mathrm{m}_{\mathrm{b}}}=1\)
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