MHT CET · Physics · Mechanical Properties of Solids

Two identical wires of substances ‘ $P$ ’ and ‘ $Q$ ’ are subjected to equal stretching force along the length. If the elongation of ‘ $Q$ ’ is more than that of ‘ $P$ ’, then

A both $P$ and $Q$ are equally elastic
B $P$ is more elastic than $Q$
C $P$ is plastic and $Q$ is elastic
D $Q$ is more elastic than $P$

Verified Solution

Answer & Solution

Correct Answer

(B) $P$ is more elastic than $Q$

Step-by-step Solution

Detailed explanation

ϒ = \frac{\frac{F}{A}}{\frac{∆ l}{l}}

\frac{F}{A} = s a m e f o r b o t h

∴ Y \propto \frac{1}{∆ l}

{(∆ l)}_{Q} > {(∆ l)}_{\begin{matrix} P \end{matrix}}

∴ Y_{P} > Y_{Q}

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From MHT CET

Explore more questions on app

Two identical wires of substances ‘ P ’ and ‘ Q ’ are subjected to equal stretching force along the length. If the elongation of ‘ Q ’ is more than that of ‘ P ’, then

Step-by-step Solution

Two identical wires of substances ‘ $P$ ’ and ‘ $Q$ ’ are subjected to equal stretching force along the length. If the elongation of ‘ $Q$ ’ is more than that of ‘ $P$ ’, then