MHT CET · Physics · Gravitation
Two identical metal spheres are kept in contact with each other, each having radius ' \(R\) ' cm and ' \(\rho\) ' is the density of material of metal spheres. The gravitational force ' \(F\) ' of attraction between them is proportional to
- A \(R^3 \rho\)
- B \(R^4 p^2\)
- C \(R^4 \rho\)
- D \(R^3 \rho^2\)
Answer & Solution
Correct Answer
(B) \(R^4 p^2\)
Step-by-step Solution
Detailed explanation

Force due to gravity,
\(\begin{aligned}
& \mathrm{F}=\frac{\mathrm{GMM}}{(2 \mathrm{R})^2} \\
& \mathrm{~F}=\frac{\mathrm{GM}^2}{4 \mathrm{R}^2}...(i)
\end{aligned}\)
Density, \(\rho=\frac{M}{V}\)
\(M=\rho \times \frac{4}{3} \pi R^3\)
Substituting in (i),
\(\begin{aligned}
& F=\frac{G\left(\frac{4}{3} \pi R^3 \rho\right)^2}{4 R^2} \\
\therefore \quad & F \propto R^4 \rho^2
\end{aligned}\)
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