MHT CET · Physics · Magnetic Effects of Current
Two identical long parallel wires carry currents ' \(\mathrm{I}_1\) ' and ' \(\mathrm{I}_2\) ' such that \(\mathrm{I}_1>\mathrm{I}_2\). When the currents are in the same direction, the magnetic field at a point midway between the wires is \(8 \times 10^{-6} \mathrm{~T}\). If the direction of \(\mathrm{I}_2\) is reversed, the field becomes \(3.2 \times 10^{-5} \mathrm{~T}\). The ratio of \(\mathrm{I}_2\) to \(\mathrm{I}_1\) is
- A \(1: 4\)
- B \(2: 5\)
- C \(3: 5\)
- D \(3: 4\)
Answer & Solution
Correct Answer
(C) \(3: 5\)
Step-by-step Solution
Detailed explanation
\(\frac{\mu_0}{\pi d}(I_1 - I_2) = 8 \times 10^{-6}\) \(\frac{\mu_0}{\pi d}(I_1 + I_2) = 3.2 \times 10^{-5}\)
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